40=2(20x)/20+x

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Solution for 40=2(20x)/20+x equation: 



40=2(20x)/20+x

We move all terms to the left:

40-(2(20x)/20+x)=0



Domain of the equation: 20+x)!=0

We move all terms containing x to the left, all other terms to the right

x)!=-20

x!=-20/1

x!=-20

x∈R



We add all the numbers together, and all the variables

-(+x+220x/20)+40=0

We get rid of parentheses

-x-220x/20+40=0

We multiply all the terms by the denominator


-x*20-220x+40*20=0

We add all the numbers together, and all the variables

-220x-x*20+800=0

Wy multiply elements

-220x-20x+800=0

We add all the numbers together, and all the variables

-240x+800=0

We move all terms containing x to the left, all other terms to the right

-240x=-800

x=-800/-240

x=3+1/3

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