40=2(2-6b)-5(b+3)

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Solution for 40=2(2-6b)-5(b+3) equation:


Simplifying
40 = 2(2 + -6b) + -5(b + 3)
40 = (2 * 2 + -6b * 2) + -5(b + 3)
40 = (4 + -12b) + -5(b + 3)

Reorder the terms:
40 = 4 + -12b + -5(3 + b)
40 = 4 + -12b + (3 * -5 + b * -5)
40 = 4 + -12b + (-15 + -5b)

Reorder the terms:
40 = 4 + -15 + -12b + -5b

Combine like terms: 4 + -15 = -11
40 = -11 + -12b + -5b

Combine like terms: -12b + -5b = -17b
40 = -11 + -17b

Solving
40 = -11 + -17b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '17b' to each side of the equation.
40 + 17b = -11 + -17b + 17b

Combine like terms: -17b + 17b = 0
40 + 17b = -11 + 0
40 + 17b = -11

Add '-40' to each side of the equation.
40 + -40 + 17b = -11 + -40

Combine like terms: 40 + -40 = 0
0 + 17b = -11 + -40
17b = -11 + -40

Combine like terms: -11 + -40 = -51
17b = -51

Divide each side by '17'.
b = -3

Simplifying
b = -3

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