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40=16/x-9.81x
We move all terms to the left:
40-(16/x-9.81x)=0
Domain of the equation: x-9.81x)!=0We add all the numbers together, and all the variables
x∈R
-(-9.81x+16/x)+40=0
We get rid of parentheses
9.81x-16/x+40=0
We multiply all the terms by the denominator
(9.81x)*x+40*x-16=0
We add all the numbers together, and all the variables
(+9.81x)*x+40*x-16=0
We add all the numbers together, and all the variables
40x+(+9.81x)*x-16=0
We multiply parentheses
9x^2+40x-16=0
a = 9; b = 40; c = -16;
Δ = b2-4ac
Δ = 402-4·9·(-16)
Δ = 2176
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2176}=\sqrt{64*34}=\sqrt{64}*\sqrt{34}=8\sqrt{34}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-8\sqrt{34}}{2*9}=\frac{-40-8\sqrt{34}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+8\sqrt{34}}{2*9}=\frac{-40+8\sqrt{34}}{18} $
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