40=1/2b(4-4b)

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Solution for 40=1/2b(4-4b) equation: 



40=1/2b(4-4b)

We move all terms to the left:

40-(1/2b(4-4b))=0



Domain of the equation: 2b(4-4b))!=0

b∈R



We add all the numbers together, and all the variables

-(1/2b(-4b+4))+40=0

We multiply all the terms by the denominator


-(1+40*2b(-4b+4))=0



We calculate terms in parentheses: -(1+40*2b(-4b+4)), so:

1+40*2b(-4b+4)

determiningTheFunctionDomain
40*2b(-4b+4)+1

Wy multiply elements

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We use the square of the difference formula

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Back to the equation:

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We calculate terms in parentheses: -(80b(-1), so:

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