40=-4(a-1)+12

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Solution for 40=-4(a-1)+12 equation: 



40=-4(a-1)+12

We move all terms to the left:

40-(-4(a-1)+12)=0



We calculate terms in parentheses: -(-4(a-1)+12), so:

-4(a-1)+12

We multiply parentheses

-4a+4+12

We add all the numbers together, and all the variables

-4a+16

Back to the equation:

-(-4a+16)



We get rid of parentheses

4a-16+40=0

We add all the numbers together, and all the variables

4a+24=0

We move all terms containing a to the left, all other terms to the right

4a=-24

a=-24/4

a=-6

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