40=-2x+5(3-x)

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Solution for 40=-2x+5(3-x) equation: 



40=-2x+5(3-x)

We move all terms to the left:

40-(-2x+5(3-x))=0

We add all the numbers together, and all the variables

-(-2x+5(-1x+3))+40=0



We calculate terms in parentheses: -(-2x+5(-1x+3)), so:

-2x+5(-1x+3)

We multiply parentheses

-2x-5x+15

We add all the numbers together, and all the variables

-7x+15

Back to the equation:

-(-7x+15)



We get rid of parentheses

7x-15+40=0

We add all the numbers together, and all the variables

7x+25=0

We move all terms containing x to the left, all other terms to the right

7x=-25

x=-25/7

x=-3+4/7

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