40=(x+3)+7+2x

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Solution for 40=(x+3)+7+2x equation: 



40=(x+3)+7+2x

We move all terms to the left:

40-((x+3)+7+2x)=0



We calculate terms in parentheses: -((x+3)+7+2x), so:

(x+3)+7+2x

determiningTheFunctionDomain
(x+3)+2x+7

We add all the numbers together, and all the variables

2x+(x+3)+7

We get rid of parentheses

2x+x+3+7

We add all the numbers together, and all the variables

3x+10

Back to the equation:

-(3x+10)



We get rid of parentheses

-3x-10+40=0

We add all the numbers together, and all the variables

-3x+30=0

We move all terms containing x to the left, all other terms to the right

-3x=-30

x=-30/-3

x=+10

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