40=(3x)+(x+5)

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Solution for 40=(3x)+(x+5) equation: 



40=(3x)+(x+5)

We move all terms to the left:

40-((3x)+(x+5))=0



We calculate terms in parentheses: -(3x+(x+5)), so:

3x+(x+5)

We get rid of parentheses

3x+x+5

We add all the numbers together, and all the variables

4x+5

Back to the equation:

-(4x+5)



We get rid of parentheses

-4x-5+40=0

We add all the numbers together, and all the variables

-4x+35=0

We move all terms containing x to the left, all other terms to the right

-4x=-35

x=-35/-4

x=8+3/4

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