400=2(2x-10)+2x

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Solution for 400=2(2x-10)+2x equation: 



400=2(2x-10)+2x

We move all terms to the left:

400-(2(2x-10)+2x)=0



We calculate terms in parentheses: -(2(2x-10)+2x), so:

2(2x-10)+2x

We add all the numbers together, and all the variables

2x+2(2x-10)

We multiply parentheses

2x+4x-20

We add all the numbers together, and all the variables

6x-20

Back to the equation:

-(6x-20)



We get rid of parentheses

-6x+20+400=0

We add all the numbers together, and all the variables

-6x+420=0

We move all terms containing x to the left, all other terms to the right

-6x=-420

x=-420/-6

x=+70

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