40/z-40/z-3=3/z

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Solution for 40/z-40/z-3=3/z equation: 


D( z )

z = 0

z = 0

z = 0

z in (-oo:0) U (0:+oo)

40/z-(40/z)-3 = 3/z // - 3/z

40/z-(40/z)-(3/z)-3 = 0

40/z-40*z^-1-3*z^-1-3 = 0

-3*z^-1 = 3 // : -3

z^-1 = -1

-1 < 0

1/(z^1) = -1 // * z^1

1 = -1*z^1 // : -1

-1 = z^1

z = -1

z = -1

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