40/(20+x)+40/(20-x)=5

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Solution for 40/(20+x)+40/(20-x)=5 equation: 


D( x )

20-x = 0

x+20 = 0

20-x = 0

20-x = 0

20-x = 0 // - 20

-x = -20 // * -1

x = 20

x+20 = 0

x+20 = 0

x+20 = 0 // - 20

x = -20

x in (-oo:-20) U (-20:20) U (20:+oo)

40/(x+20)+40/(20-x) = 5 // - 5

40/(x+20)+40/(20-x)-5 = 0

(40*(20-x))/((x+20)*(20-x))+(40*(x+20))/((x+20)*(20-x))+(-5*(x+20)*(20-x))/((x+20)*(20-x)) = 0

40*(20-x)+40*(x+20)-5*(x+20)*(20-x) = 0

5*x^2-2000+1600 = 0

5*x^2-400 = 0

(5*x^2-400)/((x+20)*(20-x)) = 0

(5*x^2-400)/((x+20)*(20-x)) = 0 // * (x+20)*(20-x)

5*x^2-400 = 0

5*x^2 = 400 // : 5

x^2 = 80

x^2 = 80 // ^ 1/2

abs(x) = 4*5^(1/2)

x = 4*5^(1/2) or x = -(4*5^(1/2))

x in { 4*5^(1/2), -(4*5^(1/2)) }

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