40-x=(3/(10-x)=

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Solution for 40-x=(3/(10-x)= equation: 



40-x=(3/(10-x)=

We move all terms to the left:

40-x-((3/(10-x))=0



Domain of the equation: (10-x))+40!=0

x∈R



We add all the numbers together, and all the variables

-x-((3/(-1x+10))+40=0

We add all the numbers together, and all the variables

-1x-((3/(-1x+10))+40=0

We multiply all the terms by the denominator


-1x*(-1x+10))+40-((3=0

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