40-5x=4(8+4x)+8

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Solution for 40-5x=4(8+4x)+8 equation: 



40-5x=4(8+4x)+8

We move all terms to the left:

40-5x-(4(8+4x)+8)=0

We add all the numbers together, and all the variables

-5x-(4(4x+8)+8)+40=0



We calculate terms in parentheses: -(4(4x+8)+8), so:

4(4x+8)+8

We multiply parentheses

16x+32+8

We add all the numbers together, and all the variables

16x+40

Back to the equation:

-(16x+40)



We get rid of parentheses

-5x-16x-40+40=0

We add all the numbers together, and all the variables

-21x=0

x=0/-21

x=0

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