40-5m=6(3-3m)+2m

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Solution for 40-5m=6(3-3m)+2m equation: 



40-5m=6(3-3m)+2m

We move all terms to the left:

40-5m-(6(3-3m)+2m)=0

We add all the numbers together, and all the variables

-5m-(6(-3m+3)+2m)+40=0



We calculate terms in parentheses: -(6(-3m+3)+2m), so:

6(-3m+3)+2m

We add all the numbers together, and all the variables

2m+6(-3m+3)

We multiply parentheses

2m-18m+18

We add all the numbers together, and all the variables

-16m+18

Back to the equation:

-(-16m+18)



We get rid of parentheses

-5m+16m-18+40=0

We add all the numbers together, and all the variables

11m+22=0

We move all terms containing m to the left, all other terms to the right

11m=-22

m=-22/11

m=-2

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