40-4(3z+5)=8

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Solution for 40-4(3z+5)=8 equation: 



40-4(3z+5)=8

We move all terms to the left:

40-4(3z+5)-(8)=0

We add all the numbers together, and all the variables

-4(3z+5)+32=0

We multiply parentheses

-12z-20+32=0

We add all the numbers together, and all the variables

-12z+12=0

We move all terms containing z to the left, all other terms to the right

-12z=-12

z=-12/-12

z=1

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