40-3x=12+4x

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Solution for 40-3x=12+4x equation:



40-3x=12+4x
We move all terms to the left:
40-3x-(12+4x)=0
We add all the numbers together, and all the variables
-3x-(4x+12)+40=0
We get rid of parentheses
-3x-4x-12+40=0
We add all the numbers together, and all the variables
-7x+28=0
We move all terms containing x to the left, all other terms to the right
-7x=-28
x=-28/-7
x=+4

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