40-2x=10+3x

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Solution for 40-2x=10+3x equation: 



40-2x=10+3x

We move all terms to the left:

40-2x-(10+3x)=0

We add all the numbers together, and all the variables

-2x-(3x+10)+40=0

We get rid of parentheses

-2x-3x-10+40=0

We add all the numbers together, and all the variables

-5x+30=0

We move all terms containing x to the left, all other terms to the right

-5x=-30

x=-30/-5

x=+6

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