40-(3c+4)=4(c+5)+c

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Solution for 40-(3c+4)=4(c+5)+c equation: 


Simplifying
40 + -1(3c + 4) = 4(c + 5) + c

Reorder the terms:
40 + -1(4 + 3c) = 4(c + 5) + c
40 + (4 * -1 + 3c * -1) = 4(c + 5) + c
40 + (-4 + -3c) = 4(c + 5) + c

Combine like terms: 40 + -4 = 36
36 + -3c = 4(c + 5) + c

Reorder the terms:
36 + -3c = 4(5 + c) + c
36 + -3c = (5 * 4 + c * 4) + c
36 + -3c = (20 + 4c) + c

Combine like terms: 4c + c = 5c
36 + -3c = 20 + 5c

Solving
36 + -3c = 20 + 5c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-5c' to each side of the equation.
36 + -3c + -5c = 20 + 5c + -5c

Combine like terms: -3c + -5c = -8c
36 + -8c = 20 + 5c + -5c

Combine like terms: 5c + -5c = 0
36 + -8c = 20 + 0
36 + -8c = 20

Add '-36' to each side of the equation.
36 + -36 + -8c = 20 + -36

Combine like terms: 36 + -36 = 0
0 + -8c = 20 + -36
-8c = 20 + -36

Combine like terms: 20 + -36 = -16
-8c = -16

Divide each side by '-8'.
c = 2

Simplifying
c = 2

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