40-(3c+4)=2(c+6)+c

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Solution for 40-(3c+4)=2(c+6)+c equation: 


Simplifying
40 + -1(3c + 4) = 2(c + 6) + c

Reorder the terms:
40 + -1(4 + 3c) = 2(c + 6) + c
40 + (4 * -1 + 3c * -1) = 2(c + 6) + c
40 + (-4 + -3c) = 2(c + 6) + c

Combine like terms: 40 + -4 = 36
36 + -3c = 2(c + 6) + c

Reorder the terms:
36 + -3c = 2(6 + c) + c
36 + -3c = (6 * 2 + c * 2) + c
36 + -3c = (12 + 2c) + c

Combine like terms: 2c + c = 3c
36 + -3c = 12 + 3c

Solving
36 + -3c = 12 + 3c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3c' to each side of the equation.
36 + -3c + -3c = 12 + 3c + -3c

Combine like terms: -3c + -3c = -6c
36 + -6c = 12 + 3c + -3c

Combine like terms: 3c + -3c = 0
36 + -6c = 12 + 0
36 + -6c = 12

Add '-36' to each side of the equation.
36 + -36 + -6c = 12 + -36

Combine like terms: 36 + -36 = 0
0 + -6c = 12 + -36
-6c = 12 + -36

Combine like terms: 12 + -36 = -24
-6c = -24

Divide each side by '-6'.
c = 4

Simplifying
c = 4

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