40-(3c+4)=2(c+3)+3

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Solution for 40-(3c+4)=2(c+3)+3 equation:


Simplifying
40 + -1(3c + 4) = 2(c + 3) + 3

Reorder the terms:
40 + -1(4 + 3c) = 2(c + 3) + 3
40 + (4 * -1 + 3c * -1) = 2(c + 3) + 3
40 + (-4 + -3c) = 2(c + 3) + 3

Combine like terms: 40 + -4 = 36
36 + -3c = 2(c + 3) + 3

Reorder the terms:
36 + -3c = 2(3 + c) + 3
36 + -3c = (3 * 2 + c * 2) + 3
36 + -3c = (6 + 2c) + 3

Reorder the terms:
36 + -3c = 6 + 3 + 2c

Combine like terms: 6 + 3 = 9
36 + -3c = 9 + 2c

Solving
36 + -3c = 9 + 2c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2c' to each side of the equation.
36 + -3c + -2c = 9 + 2c + -2c

Combine like terms: -3c + -2c = -5c
36 + -5c = 9 + 2c + -2c

Combine like terms: 2c + -2c = 0
36 + -5c = 9 + 0
36 + -5c = 9

Add '-36' to each side of the equation.
36 + -36 + -5c = 9 + -36

Combine like terms: 36 + -36 = 0
0 + -5c = 9 + -36
-5c = 9 + -36

Combine like terms: 9 + -36 = -27
-5c = -27

Divide each side by '-5'.
c = 5.4

Simplifying
c = 5.4

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