40-(2c+3)=2(c+6)+6

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Solution for 40-(2c+3)=2(c+6)+6 equation:


Simplifying
40 + -1(2c + 3) = 2(c + 6) + 6

Reorder the terms:
40 + -1(3 + 2c) = 2(c + 6) + 6
40 + (3 * -1 + 2c * -1) = 2(c + 6) + 6
40 + (-3 + -2c) = 2(c + 6) + 6

Combine like terms: 40 + -3 = 37
37 + -2c = 2(c + 6) + 6

Reorder the terms:
37 + -2c = 2(6 + c) + 6
37 + -2c = (6 * 2 + c * 2) + 6
37 + -2c = (12 + 2c) + 6

Reorder the terms:
37 + -2c = 12 + 6 + 2c

Combine like terms: 12 + 6 = 18
37 + -2c = 18 + 2c

Solving
37 + -2c = 18 + 2c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2c' to each side of the equation.
37 + -2c + -2c = 18 + 2c + -2c

Combine like terms: -2c + -2c = -4c
37 + -4c = 18 + 2c + -2c

Combine like terms: 2c + -2c = 0
37 + -4c = 18 + 0
37 + -4c = 18

Add '-37' to each side of the equation.
37 + -37 + -4c = 18 + -37

Combine like terms: 37 + -37 = 0
0 + -4c = 18 + -37
-4c = 18 + -37

Combine like terms: 18 + -37 = -19
-4c = -19

Divide each side by '-4'.
c = 4.75

Simplifying
c = 4.75

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