40-(1/22)(4x)=30-(1/22)(3x)

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Solution for 40-(1/22)(4x)=30-(1/22)(3x) equation:



40-(1/22)(4x)=30-(1/22)(3x)
We move all terms to the left:
40-(1/22)(4x)-(30-(1/22)(3x))=0
Domain of the equation: 22)4x!=0
x!=0/1
x!=0
x∈R
Domain of the equation: 22)3x)!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
-(+1/22)4x-(30-(+1/22)3x)+40=0
We multiply parentheses
-4x^2-(30-(+1/22)3x)+40=0
We multiply all the terms by the denominator
-4x^2*22)3x)-(30-(+40*22)3x)+1=0
We add all the numbers together, and all the variables
-4x^2*22)3x)-(30-8803x)+1=0
Wy multiply elements
-88x^3=0
We do not support expression: x^3

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