40+c+(c-20)=180

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Solution for 40+c+(c-20)=180 equation: 



40+c+(c-20)=180

We move all terms to the left:

40+c+(c-20)-(180)=0

We add all the numbers together, and all the variables

c+(c-20)-140=0

We get rid of parentheses

c+c-20-140=0

We add all the numbers together, and all the variables

2c-160=0

We move all terms containing c to the left, all other terms to the right

2c=160

c=160/2

c=80

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