40+5x=-2(1+8x)+7

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Solution for 40+5x=-2(1+8x)+7 equation: 



40+5x=-2(1+8x)+7

We move all terms to the left:

40+5x-(-2(1+8x)+7)=0

We add all the numbers together, and all the variables

5x-(-2(8x+1)+7)+40=0



We calculate terms in parentheses: -(-2(8x+1)+7), so:

-2(8x+1)+7

We multiply parentheses

-16x-2+7

We add all the numbers together, and all the variables

-16x+5

Back to the equation:

-(-16x+5)



We get rid of parentheses

5x+16x-5+40=0

We add all the numbers together, and all the variables

21x+35=0

We move all terms containing x to the left, all other terms to the right

21x=-35

x=-35/21

x=-1+2/3

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