40+5r=-8(1-7r)-3r

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Solution for 40+5r=-8(1-7r)-3r equation: 



40+5r=-8(1-7r)-3r

We move all terms to the left:

40+5r-(-8(1-7r)-3r)=0

We add all the numbers together, and all the variables

5r-(-8(-7r+1)-3r)+40=0



We calculate terms in parentheses: -(-8(-7r+1)-3r), so:

-8(-7r+1)-3r

We add all the numbers together, and all the variables

-3r-8(-7r+1)

We multiply parentheses

-3r+56r-8

We add all the numbers together, and all the variables

53r-8

Back to the equation:

-(53r-8)



We get rid of parentheses

5r-53r+8+40=0

We add all the numbers together, and all the variables

-48r+48=0

We move all terms containing r to the left, all other terms to the right

-48r=-48

r=-48/-48

r=1

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