40+4y-16=13y-12-3y=

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Solution for 40+4y-16=13y-12-3y= equation: 



40+4y-16=13y-12-3y=

We move all terms to the left:

40+4y-16-(13y-12-3y)=0

We add all the numbers together, and all the variables

4y-(10y-12)+40-16=0

We add all the numbers together, and all the variables

4y-(10y-12)+24=0

We get rid of parentheses

4y-10y+12+24=0

We add all the numbers together, and all the variables

-6y+36=0

We move all terms containing y to the left, all other terms to the right

-6y=-36

y=-36/-6

y=+6

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