40+3y-15=11y-11-2y

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Solution for 40+3y-15=11y-11-2y equation: 



40+3y-15=11y-11-2y

We move all terms to the left:

40+3y-15-(11y-11-2y)=0

We add all the numbers together, and all the variables

3y-(9y-11)+40-15=0

We add all the numbers together, and all the variables

3y-(9y-11)+25=0

We get rid of parentheses

3y-9y+11+25=0

We add all the numbers together, and all the variables

-6y+36=0

We move all terms containing y to the left, all other terms to the right

-6y=-36

y=-36/-6

y=+6

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