40+10w=(180-36w)/3

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Solution for 40+10w=(180-36w)/3 equation:



40+10w=(180-36w)/3
We move all terms to the left:
40+10w-((180-36w)/3)=0
We add all the numbers together, and all the variables
10w-((-36w+180)/3)+40=0
We multiply all the terms by the denominator
10w*3)-((-36w+180)+40*3)=0
We add all the numbers together, and all the variables
10w*3)-((-36w+180)=0
Wy multiply elements
30w^2=0
a = 30; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·30·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$w=\frac{-b}{2a}=\frac{0}{60}=0$

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