40+(3c+4)=4(c+5)+c

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Solution for 40+(3c+4)=4(c+5)+c equation: 


Simplifying
40 + (3c + 4) = 4(c + 5) + c

Reorder the terms:
40 + (4 + 3c) = 4(c + 5) + c

Remove parenthesis around (4 + 3c)
40 + 4 + 3c = 4(c + 5) + c

Combine like terms: 40 + 4 = 44
44 + 3c = 4(c + 5) + c

Reorder the terms:
44 + 3c = 4(5 + c) + c
44 + 3c = (5 * 4 + c * 4) + c
44 + 3c = (20 + 4c) + c

Combine like terms: 4c + c = 5c
44 + 3c = 20 + 5c

Solving
44 + 3c = 20 + 5c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-5c' to each side of the equation.
44 + 3c + -5c = 20 + 5c + -5c

Combine like terms: 3c + -5c = -2c
44 + -2c = 20 + 5c + -5c

Combine like terms: 5c + -5c = 0
44 + -2c = 20 + 0
44 + -2c = 20

Add '-44' to each side of the equation.
44 + -44 + -2c = 20 + -44

Combine like terms: 44 + -44 = 0
0 + -2c = 20 + -44
-2c = 20 + -44

Combine like terms: 20 + -44 = -24
-2c = -24

Divide each side by '-2'.
c = 12

Simplifying
c = 12

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