40(x-1)=8(5-x)+32x

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Solution for 40(x-1)=8(5-x)+32x equation: 



40(x-1)=8(5-x)+32x

We move all terms to the left:

40(x-1)-(8(5-x)+32x)=0

We add all the numbers together, and all the variables

40(x-1)-(8(-1x+5)+32x)=0

We multiply parentheses

40x-(8(-1x+5)+32x)-40=0



We calculate terms in parentheses: -(8(-1x+5)+32x), so:

8(-1x+5)+32x

We add all the numbers together, and all the variables

32x+8(-1x+5)

We multiply parentheses

32x-8x+40

We add all the numbers together, and all the variables

24x+40

Back to the equation:

-(24x+40)



We get rid of parentheses

40x-24x-40-40=0

We add all the numbers together, and all the variables

16x-80=0

We move all terms containing x to the left, all other terms to the right

16x=80

x=80/16

x=5

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