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4/y-3=5/2y-3
We move all terms to the left:
4/y-3-(5/2y-3)=0
Domain of the equation: y!=0
y∈R
Domain of the equation: 2y-3)!=0We get rid of parentheses
y∈R
4/y-5/2y+3-3=0
We calculate fractions
8y/2y^2+(-5y)/2y^2+3-3=0
We add all the numbers together, and all the variables
8y/2y^2+(-5y)/2y^2=0
We multiply all the terms by the denominator
8y+(-5y)=0
We get rid of parentheses
8y-5y=0
We add all the numbers together, and all the variables
3y=0
y=0/3
y=0
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