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4/x=6/2x+3
We move all terms to the left:
4/x-(6/2x+3)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 2x+3)!=0We get rid of parentheses
x∈R
4/x-6/2x-3=0
We calculate fractions
8x/2x^2+(-6x)/2x^2-3=0
We multiply all the terms by the denominator
8x+(-6x)-3*2x^2=0
Wy multiply elements
-6x^2+8x+(-6x)=0
We get rid of parentheses
-6x^2+8x-6x=0
We add all the numbers together, and all the variables
-6x^2+2x=0
a = -6; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·(-6)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*-6}=\frac{-4}{-12} =1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*-6}=\frac{0}{-12} =0 $
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