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4/x-2=x-6/x+3
We move all terms to the left:
4/x-2-(x-6/x+3)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: x+3)!=0We get rid of parentheses
x∈R
4/x-x+6/x-3-2=0
We multiply all the terms by the denominator
-x*x-3*x-2*x+4+6=0
We add all the numbers together, and all the variables
-5x-x*x+10=0
Wy multiply elements
-1x^2-5x+10=0
a = -1; b = -5; c = +10;
Δ = b2-4ac
Δ = -52-4·(-1)·10
Δ = 65
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{65}}{2*-1}=\frac{5-\sqrt{65}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{65}}{2*-1}=\frac{5+\sqrt{65}}{-2} $
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