4/x-2-3/x+1=8/(x-2)(x+1)

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Solution for 4/x-2-3/x+1=8/(x-2)(x+1) equation:



4/x-2-3/x+1=8/(x-2)(x+1)
We move all terms to the left:
4/x-2-3/x+1-(8/(x-2)(x+1))=0
Domain of the equation: x!=0
x∈R
Domain of the equation: (x-2)(x+1))!=0
x∈R
We add all the numbers together, and all the variables
4/x-3/x-(8/(x-2)(x+1))-1=0
We multiply parentheses ..
-(8/(+x^2+x-2x-2))+4/x-3/x-1=0
We calculate fractions
We do not support expression: x^3

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