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4/x+5/4x-1/4=5
We move all terms to the left:
4/x+5/4x-1/4-(5)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 4x!=0determiningTheFunctionDomain 4/x+5/4x-5-1/4=0
x!=0/4
x!=0
x∈R
We calculate fractions
256x/64x^2+5x/64x^2+(-x)/64x^2-5=0
We add all the numbers together, and all the variables
256x/64x^2+5x/64x^2+(-1x)/64x^2-5=0
We multiply all the terms by the denominator
256x+5x+(-1x)-5*64x^2=0
We add all the numbers together, and all the variables
261x+(-1x)-5*64x^2=0
Wy multiply elements
-320x^2+261x+(-1x)=0
We get rid of parentheses
-320x^2+261x-1x=0
We add all the numbers together, and all the variables
-320x^2+260x=0
a = -320; b = 260; c = 0;
Δ = b2-4ac
Δ = 2602-4·(-320)·0
Δ = 67600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{67600}=260$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(260)-260}{2*-320}=\frac{-520}{-640} =13/16 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(260)+260}{2*-320}=\frac{0}{-640} =0 $
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