4/x+3=10/2x-1

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Solution for 4/x+3=10/2x-1 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

4/x+3 = (10/2)*x-1 // - (10/2)*x-1

4/x-((10/2)*x)+1+3 = 0

4/x-5*x+1+3 = 0

4*x^-1-5*x^1+4*x^0 = 0

(4*x^1-5*x^2+4*x^0)/(x^1) = 0 // * x^2

x^1*(4*x^1-5*x^2+4*x^0) = 0

x^1

4*x-5*x^2+4 = 0

4*x-5*x^2+4 = 0

DELTA = 4^2-(-5*4*4)

DELTA = 96

DELTA > 0

x = (96^(1/2)-4)/(-5*2) or x = (-96^(1/2)-4)/(-5*2)

x = (4*6^(1/2)-4)/(-10) or x = (-4*6^(1/2)-4)/(-10)

x in { (4*6^(1/2)-4)/(-10), (-4*6^(1/2)-4)/(-10)} 

x in { (4*6^(1/2)-4)/(-10), (-4*6^(1/2)-4)/(-10) }

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