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4/x+2)+6=14/2x+4
We move all terms to the left:
4/x+2)+6-(14/2x+4)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
4/x+2)+6-(14/2x=0
We calculate fractions
8x/2x^2-(14*x)/2x^2+6+2=0
We add all the numbers together, and all the variables
8x/2x^2-(+14x)/2x^2+6+2=0
We add all the numbers together, and all the variables
8x/2x^2-(+14x)/2x^2+8=0
We multiply all the terms by the denominator
8x-(+14x)+8*2x^2=0
Wy multiply elements
16x^2+8x-(+14x)=0
We get rid of parentheses
16x^2+8x-14x=0
We add all the numbers together, and all the variables
16x^2-6x=0
a = 16; b = -6; c = 0;
Δ = b2-4ac
Δ = -62-4·16·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6}{2*16}=\frac{0}{32} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6}{2*16}=\frac{12}{32} =3/8 $
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