4/n+1/8=7/2n

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Solution for 4/n+1/8=7/2n equation:


D( n )

n = 0

n = 0

n = 0

n in (-oo:0) U (0:+oo)

4/n+1/8 = (7/2)*n // - (7/2)*n

4/n-((7/2)*n)+1/8 = 0

(-7/2)*n+4/n+1/8 = 0

4*n^-1-7/2*n^1+1/8*n^0 = 0

(1/8*n^1-7/2*n^2+4*n^0)/(n^1) = 0 // * n^2

n^1*(1/8*n^1-7/2*n^2+4*n^0) = 0

n^1

(-7/2)*n^2+(1/8)*n+4 = 0

(-7/2)*n^2+(1/8)*n+4 = 0

DELTA = (1/8)^2-(4*4*(-7/2))

DELTA = 3585/64

DELTA > 0

n = ((3585/64)^(1/2)-(1/8))/(2*(-7/2)) or n = (-(1/8)-(3585/64)^(1/2))/(2*(-7/2))

n = ((3585/64)^(1/2)-1/8)/(-7) or n = ((3585/64)^(1/2)+1/8)/7

n in { ((3585/64)^(1/2)-1/8)/(-7), ((3585/64)^(1/2)+1/8)/7}

n in { ((3585/64)^(1/2)-1/8)/(-7), ((3585/64)^(1/2)+1/8)/7 }

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