4/9a2=1

Solution for 4/9a2=1 equation:

4/9a^2=1

We move all terms to the left:

4/9a^2-(1)=0


Domain of the equation: 9a^2!=0

a^2!=0/9

a^2!=√0

a!=0

a∈R


We multiply all the terms by the denominator


-1*9a^2+4=0

Wy multiply elements

-9a^2+4=0

a = -9; b = 0; c = +4;
Δ = b2-4ac
Δ = 02-4·(-9)·4
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12}{2*-9}=\frac{-12}{-18}
=2/3
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12}{2*-9}=\frac{12}{-18}
=-2/3
$