4/8y-3y/y-1=2

Solution for 4/8y-3y/y-1=2 equation:

4/8y-3y/y-1=2

We move all terms to the left:

4/8y-3y/y-1-(2)=0


Domain of the equation: 8y!=0

y!=0/8

y!=0

y∈R



Domain of the equation: y!=0

y∈R


We add all the numbers together, and all the variables

4/8y-3y/y-3=0

We calculate fractions


(-24y^2)/8y^2+4y/8y^2-3=0

We multiply all the terms by the denominator


(-24y^2)+4y-3*8y^2=0

Wy multiply elements

(-24y^2)-24y^2+4y=0

We get rid of parentheses

-24y^2-24y^2+4y=0

We add all the numbers together, and all the variables

-48y^2+4y=0

a = -48; b = 4; c = 0;
Δ = b2-4ac
Δ = 42-4·(-48)·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4}{2*-48}=\frac{-8}{-96}
=1/12
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4}{2*-48}=\frac{0}{-96}
=0
$