4/7x+5/14x=49

Solution for 4/7x+5/14x=49 equation:

4/7x+5/14x=49

We move all terms to the left:

4/7x+5/14x-(49)=0


Domain of the equation: 7x!=0

x!=0/7

x!=0

x∈R



Domain of the equation: 14x!=0

x!=0/14

x!=0

x∈R


We calculate fractions


56x/98x^2+35x/98x^2-49=0

We multiply all the terms by the denominator


56x+35x-49*98x^2=0

We add all the numbers together, and all the variables

91x-49*98x^2=0

Wy multiply elements

-4802x^2+91x=0

a = -4802; b = 91; c = 0;
Δ = b2-4ac
Δ = 912-4·(-4802)·0
Δ = 8281
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{8281}=91$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(91)-91}{2*-4802}=\frac{-182}{-9604}
=13/686
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(91)+91}{2*-4802}=\frac{0}{-9604}
=0
$