4/7m=2/7(2m+1)

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Solution for 4/7m=2/7(2m+1) equation: 


m in (-oo:+oo)

(4/7)*m = (2/7)*(2*m+1) // - (2/7)*(2*m+1)

(4/7)*m-((2/7)*(2*m+1)) = 0

(-2/7)*(2*m+1)+(4/7)*m = 0

(4*m)/7-2/7*(2*m+1) = 0

(-2/7*7*(2*m+1))/7+(4*m)/7 = 0

4*m-2/7*7*(2*m+1) = 0

-2 = 0

-2/7 = 0

-2/7 = 0 // * 7

-2 = 0

m belongs to the empty set

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