4/7/3=12/n

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Solution for 4/7/3=12/n equation: 


D( n )

n = 0

n = 0

n = 0

n in (-oo:0) U (0:+oo)

(4/7)/3 = 12/n // - 12/n

(4/7)/3-(12/n) = 0

(4/7)/3-12*n^-1 = 0

-12*n^-1 = -4/21 // : -12

n^-1 = 1/63

-1 < 0

1/(n^1) = 1/63 // * n^1

1 = 1/63*n^1 // : 1/63

63 = n^1

n = 63

n = 63

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