4/7(3X+2)+3/2x=1/2(7x+10)

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Solution for 4/7(3X+2)+3/2x=1/2(7x+10) equation: 



4/7(3X+2)+3/2X=1/2(7X+10)

We move all terms to the left:

4/7(3X+2)+3/2X-(1/2(7X+10))=0



Domain of the equation: 7(3X+2)!=0

X∈R





Domain of the equation: 2X!=0

X!=0/2

X!=0

X∈R





Domain of the equation: 2(7X+10))!=0

X∈R



We calculate fractions


32X^2/(7(3X+2)*2X*2(7X+10)))+(42X^23/(7(3X+2)*2X*2(7X+10)))+(-(1*7(3X+2)*2X)/(7(3X+2)*2X*2(7X+10)))=0



We calculate terms in parentheses: -(1*7(3X+2)*2X)/(7(3X+2)*2X*2(7X+10))), so:

1*7(3X+2)*2X)/(7(3X+2)*2X*2(7X+10))

We multiply all the terms by the denominator


1*7(3X+2)*2X)

Wy multiply elements

14X^2(3

Back to the equation:

-(14X^2(3)



We do not support eXpression: X^23

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