4/7(28n-35)=2/3(24n-30)

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Solution for 4/7(28n-35)=2/3(24n-30) equation: 


n in (-oo:+oo)

(4/7)*(28*n-35) = (2/3)*(24*n-30) // - (2/3)*(24*n-30)

(4/7)*(28*n-35)-((2/3)*(24*n-30)) = 0

(4/7)*(28*n-35)+(-2/3)*(24*n-30) = 0

4/7*(28*n-35)-2/3*(24*n-30) = 0

4/7*(28*n-35)-2/3*(24*n-30) = 0

0 = 0

0 = 0

n belongs to the empty set

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