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4/6n+8=1/2n+2
We move all terms to the left:
4/6n+8-(1/2n+2)=0
Domain of the equation: 6n!=0
n!=0/6
n!=0
n∈R
Domain of the equation: 2n+2)!=0We get rid of parentheses
n∈R
4/6n-1/2n-2+8=0
We calculate fractions
8n/12n^2+(-6n)/12n^2-2+8=0
We add all the numbers together, and all the variables
8n/12n^2+(-6n)/12n^2+6=0
We multiply all the terms by the denominator
8n+(-6n)+6*12n^2=0
Wy multiply elements
72n^2+8n+(-6n)=0
We get rid of parentheses
72n^2+8n-6n=0
We add all the numbers together, and all the variables
72n^2+2n=0
a = 72; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·72·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*72}=\frac{-4}{144} =-1/36 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*72}=\frac{0}{144} =0 $
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