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4/5x-8=4(1/5x+2)
We move all terms to the left:
4/5x-8-(4(1/5x+2))=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 5x+2))!=0We calculate fractions
x∈R
20x/25x^2+(-(4(1*5x)/25x^2-8=0
We add all the numbers together, and all the variables
20x/25x^2+(-(4(+1*5x)/25x^2-8=0
We calculate fractions
We do not support expression: x^4
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