4/5x-6+1/4x=19/20+x

Solution for 4/5x-6+1/4x=19/20+x equation:

4/5x-6+1/4x=19/20+x

We move all terms to the left:

4/5x-6+1/4x-(19/20+x)=0


Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R



Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R



Domain of the equation: 20+x)!=0

We move all terms containing x to the left, all other terms to the right

x)!=-20

x!=-20/1

x!=-20

x∈R


We add all the numbers together, and all the variables

4/5x+1/4x-(+x+19/20)-6=0

We get rid of parentheses

4/5x+1/4x-x-6-19/20=0

We calculate fractions


(-1520x^2)/800x^2-x+640x/800x^2+200x/800x^2-6=0

We add all the numbers together, and all the variables

(-1520x^2)/800x^2-1x+640x/800x^2+200x/800x^2-6=0

We multiply all the terms by the denominator


(-1520x^2)-1x*800x^2+640x+200x-6*800x^2=0

We add all the numbers together, and all the variables

(-1520x^2)+840x-1x*800x^2-6*800x^2=0

Wy multiply elements

(-1520x^2)-800x^3-4800x^2+840x=0

We get rid of parentheses

-1520x^2-800x^3-4800x^2+840x=0

We do not support expression: x^3