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4/5x-3=-8x-3
We move all terms to the left:
4/5x-3-(-8x-3)=0
Domain of the equation: 5x!=0We get rid of parentheses
x!=0/5
x!=0
x∈R
4/5x+8x+3-3=0
We multiply all the terms by the denominator
8x*5x+3*5x-3*5x+4=0
Wy multiply elements
40x^2+15x-15x+4=0
We add all the numbers together, and all the variables
40x^2+4=0
a = 40; b = 0; c = +4;
Δ = b2-4ac
Δ = 02-4·40·4
Δ = -640
Delta is less than zero, so there is no solution for the equation
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