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4/5x-15=3x+3
We move all terms to the left:
4/5x-15-(3x+3)=0
Domain of the equation: 5x!=0We get rid of parentheses
x!=0/5
x!=0
x∈R
4/5x-3x-3-15=0
We multiply all the terms by the denominator
-3x*5x-3*5x-15*5x+4=0
Wy multiply elements
-15x^2-15x-75x+4=0
We add all the numbers together, and all the variables
-15x^2-90x+4=0
a = -15; b = -90; c = +4;
Δ = b2-4ac
Δ = -902-4·(-15)·4
Δ = 8340
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{8340}=\sqrt{4*2085}=\sqrt{4}*\sqrt{2085}=2\sqrt{2085}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-90)-2\sqrt{2085}}{2*-15}=\frac{90-2\sqrt{2085}}{-30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-90)+2\sqrt{2085}}{2*-15}=\frac{90+2\sqrt{2085}}{-30} $
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